436566
7
Zoom out
Zoom in
Previous page
1/8
Next page
EL-520W (TINSExxxxEHZZ)_ENGLISH_OpExam
k&~£pnzw^
¢PZWvrab©
xy≠° (t, P(, Q(, R()
DATA
95 m10
0.
80 95 k
1.
80 80 k
2.
75 k
3.
75 75 & 3 k
4.
75 50 k
5.
50
x= R~
75.71428571
σx= Rp
12.37179148
n= Rn
7.
Σx= Rz
530.
Σx
2
= Rw
41’200.
sx=
13.3630621
sx
2
= L=
178.5714286
(95–
x)
×10+50=
( 95 -K~)
sx
/K£* 10
+ 50 =
64.43210706
x = 60 P(t) ? °1 60 °0)=
0.102012
t = –0.5 R(t) ? °3 0.5 ±)=
0.691463
xy m11
0.
2 5 2 & 5 k
1.
2 5 k
2.
12 24 12 & 24 k
3.
21 40 21 & 40 & 3 k
4.
21 40 15 & 25 k
5.
21 40 Ra
1.050261097
15 25 Rb
1.826044386
Rr
0.995176343
8.541216597
15.67223812
x=3 y=? 3 @y
6.528394256
y=46 x=? 46 @x
24.61590706
xy m12
0.
12 41 12 & 41 k
1.
8 13 8 & 13 k
2.
5 2 5 & 2 k
3.
23 200 23 & 200 k
4.
15 71 15 & 71 k
5.
Ra
5.357506761
Rb
–3.120289663
0.503334057
x=10 y=? 10 @y
24.4880159
y=22 x=? 22 @x
9.63201409
@≠
–3.432772026
@≠
9.63201409
k[]
DATA
30 m10
0.
40 30 k
1.
40 40 & 2 k
2.
50 50 k
3.
DATA
30 ]]]
45 45 & 3 k X2=
45.
45 ] N2=
3.
45
60 ] 60 k X3=
60.
stdDv L1 = 2.516611478
ª∑46∑00=
vari L1 = 6.333333333
ª∑47∑00=
o_prod(L1,L2) = {–24 –4 19}
ª
∑48∑00
@,∑01)=
i_prod(L1,L2) = –29
ª
∑49∑00
@,∑01)=
abs L2 = 5.099019514
ª∑4A∑01=
list matA matA: 2 –3
list matA matA: 7 –1 ª∑6
list matA matA: 4 –4
Function Dynamic range
Funktion zulässiger Bereich
Fonction Plage dynamique
Función Rango dinámico
Função Gama dinâmica
Funzioni Campi dinamici
Functie Rekencapaciteit
Függvény Megengedett számítási tartomány
Funkce Dynamický rozsah
Funktion Definitionsområde
Funktio Dynaaminen ala
îÛÌ͈Ëfl ÑË̇Ï˘ÂÒÍËÈ ‰Ë‡Ô‡ÁÓÌ
Funktion Dynamikområde
Fungsi Julat dinamik
Fungsi Kisaran dinamis
DEG: | x | < 10
10
(tan x : | x | 90 (2n–1))*
sin x, cos x,
RAD: | x | < —– × 10
10
tan x (tan x : | x | — (2n–1))*
GRAD: | x | < —– × 10
10
(tan x : | x | 100 (2n–1))*
sin
–1
x
,
cos
1
x | x | 1
tan
1
x,
3
¿
x | x | < 10
100
In x
,
log x 10
99
x < 10
100
y > 0: 10
100
< x log y < 100
y = 0: 0 < x < 10
100
y
x
y < 0: x = n
(0 < l x l < 1: = 2n1, x 0)*,
10
100
< x log | y | < 100
y > 0: 10
100
< log y < 100 (x 0)
y = 0: 0 < x < 10
100
x
¿y y < 0: x = 2n1
(0 < | x | < 1 : = n, x 0)*,
10
100
< log | y | < 100
e
x
10
100
< x 230.2585092
10
x
10
100
< x < 100
sinh x,
cosh x,
| x | 230.2585092
tanh x
sinh
1
x | x | < 10
50
cosh
1
x 1 x < 10
50
tanh
1
x | x | < 1
x
2
| x | < 10
50
x
3
| x | < 2.15443469 × 10
33
¿
x 0 x < 10
100
x
1
| x | < 10
100
(x 0)
n! 0 n 69*
nPr
0 r n 9999999999*
—— < 10
100
nCr
0 r n 9999999999*
0 r 69
—— < 10
100
DEG, D°MS
0°00.00001 | x | < 10000°
x, y r, θ x
2
+ y
2
< 10
100
0 r < 10
100
DEG: | θ | < 10
10
r, θ x, y RAD: | θ | < —– × 10
10
GRAD : | θ | < × 10
10
DEGRAD, GRADDEG: | x | < 10
100
DRG |
RADGRAD: | x | <
× 10
98
(A+Bi)+(C+Di) | A + C | < 10
100
, | B + D | < 10
100
(A+Bi)(C+Di)| A C | < 10
100
, | B D | < 10
100
(A+Bi)×(C+Di)
(AC BD) < 10
100
(AD + BC) < 10
100
@{ 8 Ö 70 + 12 Ö 25
= [r]
18.5408873
i
@≠ [θ]
42.76427608
i
r1 = 8, θ1 = 70°
r2 = 12, θ2 = 25°
r = ?, θ = ?°
(1 + i) @} 1 +Ü=
1.
i
@{ [r]
1.414213562
i
r = ?, θ = ?° @≠ [θ]
45.
i
@}( 2 - 3 Ü)L
(2 3i)
2
= = [x]
–5.
i
@≠ [y]
12.
i
1 ( 1 +Ü)@•= [x]
0.5
i
1 + i @≠ [y]
0.5
i
CONJ(5+2i)
∑0( 5 + 2 Ü)= [x]
5.
i
@≠ [y]
2.
i
m (MAT)
m4
1 2
matA
] 2 k 2 k 1 k 2 k
3 4 3 k 4 k
3 1
matB
ª∑20
2 6
] 2 k 2 k
3 k 1 k 2 k 6 k
ª∑21
matA × matB =
7 13
ª∑00*∑01=
17 27
matA
1
=
2
1
ª∑00@•=
1.5 0.5
dim(matA,3,3) = 1 2 0
ª∑30∑00
dim(matA,3,3) = 3 4 0
@, 3 @, 3 )=
dim(matA,3,3) = 0 0 0
fill(5,3,3) = 5 5 5
ª∑31 5 @,
fill(5,3,3) = 5 5 5
3 @, 3 )=
fill(5,3,3) = 5 5 5
cumul matA =
1 2
ª∑32∑00=
4 6
aug(matA,matB) =
1 2 3 1 ª∑33∑00
3 4 2 6 @,∑01)=
identity 3 = 1 0 0
identity 3 = 0 1 0 ª∑34 3 =
identity 3 = 0 0 1
rnd_mat(2,3)
ª∑35 2 @, 3 )=
det matA = 2
ª∑40∑00=
trans matB =
3 2
ª∑41∑01=
1 6
mat list
L1: {1 3}
ª∑5
L2: {3 2}
m (LIST)
m5
2, 7, 4 L1 ] 3 k 2 k 7 k 4 k
3, 1, 4 L2
ª∑20
] 3 k
± 3 1 4 k
ª∑21
L1+L2 = {1 6 0}
ª∑00+∑01=
sortA L1 = {2 4 7}
ª∑30∑00=
sortD L1 = {7 4 2}
ª∑31∑00=
dim(L1,5) = {2 7 4 0 0}
ª∑32∑00
@, 5 )=
fill(5,5) = {5 5 5 5 5}
ª∑33 5 @,
5 )=
cumul L1 = {2 9 13}
ª∑34∑00=
df_list L1 = {5 3}
ª∑35∑00=
aug(L1,L2) = {2 7 4 3 1 4} ª∑36∑00
@,∑01)=
min L1 = 2
ª∑40∑00=
max L1 = 7
ª∑41∑00=
mean L1 = 4.333333333
ª∑42∑00=
med L1 = 4
ª∑43∑00=
sum L1 = 13
ª∑44∑00=
prod L1 = 56
ª∑45∑00=
o_° (sec, min)
12°3918.05 ª 12 o 39 o 18.05
[10] @_
12.65501389
123.678[60] 123.678 @_
123°40’40.8”
3h30m45s + 3 o 30 o 45 + 6 o
6h45m36s = [60] 45 o 36 =
10°16’21.”
1234°5612 + 1234 o 56 o 12 +
0°034.567 = [60] 0 o 0 o 34.567 =
1234°56’47.”
3h45m 3 o 45 - 1.69 =
1.69h = [60] @_
2°3’36.”
sin62°1224 = [10] s 62 o 12 o 24=
0.884635235
24°[ ] 24 o°2
86’400.
1500[ ]0 o 0 o 1500 °3
25.
{},≠
ª 6 @, 4
x = 6
r = @{[
r
]
7.211102551
y = 4 θ = [°] @≠[θ]
33.69006753
@≠[
r
]
7.211102551
14 @, 36
r = 14
x = @}[x]
11.32623792
θ = 36[°] y = @≠[y]
8.228993532
@≠[x]
11.32623792
ß
V
0
= 15.3m/s ª 15.3 * 10 + 2 @•*
t = 10s ß 03 * 10 L=
643.3325
V
0
t+ gt
2
= ?m
¥
125yd = ?m ª 125 5 =
114.3
(k, M, G, T, m,
ÌÌ
ÌÌ
Ì, n, p, f)
100m×10k= 100 ∑14*
10 ∑10=
1’000.
j”
5÷9=ANS ª”10”2 1
ANS×9= 5 / 9 =
0.6
[FIX,TAB=1] * 9 =*
1
5.0
5 / 9 =@j
0.6
* 9 =*
2
5.4
”13
*
1
5.5555555555555×10
1
×9
*
2
0.6×9
(SOLV)
sin x0.5 ªsKˆ- 0.5
Start= 0 ∑0 0 ®®
30.
Start= 180 ® 180 ®®
150.
m0
f(x) = x
3
3x
2
+2 Kˆ™ 3 - 3 K
ˆL+ 2 @≤
x = 11 ±®
–2.
x = 0.5 @≤ 0.5 ±®
1.125
A
2
+B
2
@⁄(KAL+
KBL)@≤
A = 2, B = 3 2 ® 3 ®
3.605551275
A = 2, B = 5 @≤® 5 ®
5.385164807
1234567890.,
1234567890.,
1234567890.,
1234567890.,
1234567890.,
1234567890.,
CALCULATION EXAMPLES
ANWENDUNGSBEISPIELE
EXEMPLES DE CALCUL
EJEMPLOS DE CÁLCULO
EXEMPLOS DE CÁLCULO
ESEMPI DI CALCOLO
REKENVOORBEELDEN
PÉLDASZÁMÍTÁSOK
PŘÍKLADY VÝPOČTŮ
RÄKNEEXEMPEL
LASKENTAESIMERKKEJÄ
èêàåÖêõ ÇõóàëãÖçàâ
UDREGNINGSEKSEMPLER
CONTOH-CONTOH PENGHITUNGAN
CONTOH-CONTOH PERHITUNGAN
EL-506W
EL-546W
[]
13(5+2)= ª 3 ( 5 + 2 )=
21.
23×5+2= 3 * 5 + 2 =
17.
33×5+3×2= 3 * 5 + 3 * 2 =
21.
1 @[
21.
2 ]
17.
3 ]
21.
2 [
17.
100000÷3=
[NORM1] ª 100000 / 3 =
33’333.33333
[FIX] ”10
33’333.33333
[TAB 2] ”2 2
33’333.33
[SCI] ”11
3.33
×
10
04
[ENG] ”12
33.33
×
10
03
[NORM1] ”13
33’333.33333
3÷1000=
[NORM1] ª 3 / 1000 =
0.003
[NORM2] ”14
3.
×
10
–03
[NORM1] ”13
0.003
+-*/()±E
45+285÷3= ª 45 + 285 / 3 =
140.
18+6
=
( 18 + 6 )/
158 ( 15 - 8 =
3.428571429
42×(5)+120= 42 5 + 120 =
–90.
*
1
(5 ±) *
1
(5×10
3
)÷(4×10
3
)= 5 E 3 / 4 E
± 3 =
1’250’000.
34+57= 34 + 57 =
91.
45+57= 45 + 57 =
102.
68×25= 68 * 25 =
1’700.
68×40= 68 * 40 =
2’720.
sutSUTVhH
Ile¡•L÷⁄™
$#!qQ%
sin60[°]= ªs 60 =
0.866025403
cos [rad]=
”01u(
@V/ 4 )=
0.707106781
tan
1
1=[g] ”02@T 1 =
50.
”00
(cosh 1.5 + ª(hu 1.5 +h
sinh 1.5)
2
= s 1.5 )L=
20.08553692
tanh
1
=
@Ht( 5
/ 7 )=
0.895879734
ln 20 = I 20 =
2.995732274
log 50 = l 50 =
1.698970004
e
3
= @e 3 =
20.08553692
10
1.7
= 1.7 =
50.11872336
+ =
6 @•+ 7 @
•=
0.309523809
8
2
3
4
× 5
2
=8 ™± 2 - 3
4 * 5 L=
–2’024.984375
(12
3
)
=
12 3 4
@•=
6.447419591
8
3
8 ÷=
512.
¿
49
4
¿
81 = @⁄ 49 - 4 @$
81 =
4.
3
¿
27 @# 27 =
3.
4! = 4 @!=
24.
10
P
3
= 10 @q 3 =
720.
5
C
2
=5 @Q 2 =
10.
500×25%= 500 * 25 @%
125.
120÷400=?% 120 / 400 @%
30.
500+(500×25%)= 500 + 25 @%
625.
400(400×30%)= 400 - 30 @%
280.
θ = sin
1
x
,
θ = tan
1
x θ = cos
1
x
DEG 90 θ 90 0 θ 180
RAD θ 0 θ π
GRAD 100 θ 100 0 θ 200
Åè
d/dx (x
4
0.5x
3
+ 6x
2
) ªKˆ™ 4 - 0.5 K
x=2 ˆ÷+ 6 KˆL
dx=0.00002 2 ®®
50.
x=3 ® 3 ® 0.001 ®
130.5000029
dx=0.001
8
2
(x
2
5)dx ªKˆL- 5
n=100 è 2 ® 8 ®®
138.
n=10 ®®® 10 ®
138.
g
90° [rad] ª 90 @g
1.570796327
[g] @g
100.
[°] @g
90.
sin
1
0.8 = [°] @S 0.8 =
53.13010235
[rad] @g
0.927295218
[g] @g
59.03344706
[°] @g
53.13010235
KRO;:?≥∆˚¬
ª 8 * 2 OM
16.
24÷(8×2)= 24 /KM=
1.5
(8×2)×5= KM* 5 =
80.
ªOM
0.
$150×3:M1 150 * 3 ;
450.
+)$250:M2 =M1+250 250 ;
250.
)M2×5% RM* 5 @%
35.
M @:RM
665.
π
2
π
2
$1=¥110 110 OY
110.
¥26,510=$? 26510 /RY=
241.
$2,750=¥? 2750 *RY=
302’500.
r=3cm (rY) 3 OY
3.
πr
2
=? @VKYL=
28.27433388
—— = 2.4...(A) 24 /( 4 + 6 )=
2.4
3×(A)+60÷(A)=
3 *K?+ 60 /
K?=
32.2
πr
2
F1 @VKYL
O≥
F1
3 OY
3.
V = ? R≥* 4 / 3 =
37.69911184
6+4=ANS ª 6 + 4 =
10.
ANS+5 + 5 =
15.
8×2=ANS 8 * 2 =
16.
ANS
2
L=
256.
44+37=ANS 44 + 37 =
81.
ANS= @⁄=
9.
\|
3 + = [a] ª 3 \ 1 \ 2 +
4 \ 3 =
4
l
5
l
6
*
[a.xxx] \
4.833333333
[d/c] @|
29
l
6
10
= 2 \ 3 =
4.641588834
(
)
5
=7 \ 5 5 =
16807
l
3125
(
)
=
1 \ 8 1 \ 3
=
1
l
2
—— = @⁄ 64 \ 225 =
8
l
15
2
3
( 2 3 ) \
3
4
( 3 4 ) =
8
l
81
1.2
1.2 \ 2.3 =
12
l
23
2.3
1°23
1 o 2 o 3 \ 2 =
0°31’1.5”
2
1×10
3
1 E 3 \ 2 E 3 =
1
l
2
2×10
3
A = 7 ª 7 OA
7.
=4 \KA=
4
l
7
1.25 + = [a.xxx] 1.25 + 2 \ 5 =
1.65
[a] \
1
l
13
l
20
*
4
l
5
l
6
= 4
êûîìíãâ†ä
àá
DEC(25)BIN ª@í 25
11001.
b
HEX(1AC) 1AC
BIN
110101100.
b
PEN
3203.
P
OCT
654.
0
DEC
428.
BIN(1010100) @ê( 1010 - 100 )
×11 = * 11 =
10010.
b
BIN(111)NEG ã 111 =
1111111001.
b
HEX(1FF)+ 1FF @î+
OCT(512)= 512 =
1511.
0
HEX(?)
349.
H
2FEC ªOM@ì 2FEC -
2C9E=(A) 2C9E ;
34E.
H
+)2000 2000 -
1901=(B) 1901 ;
6FF.
H
(C) RM
A4d.
H
1011 AND ª@ê 1011
101 = (BIN) 101 =
1.
b
5A OR C3 = (HEX) 5A ä C3 =
db.
H
NOT 10110 = @êâ 10110 =
1111101001.
b
(BIN)
24 XOR 4 = (OCT) 24 à 4 =
20.
0
B3 XNOR B3 á
2D = (HEX) 2D =
FFFFFFFF61.
H
DEC
–159.
t = ––––
x x
σx
Standardization conversion formula
Standard Umrechnungsformel
Formule de conversion de standardisation
Fórmula de conversión de estandarización
Fórmula de conversão padronizada
Formula di conversione della standardizzazione
Standaardisering omzettingsformule
Standard átváltási képlet
Vzorec pro přepočet rozdělení
Omvandlingsformel för standardisering
Normituksen konversiokaava
îÓÏÛ· Òڇ̉‡ÚËÁÓ‚‡ÌÌÓ„Ó ÔÂÓ·‡ÁÓ‚‡ÌËfl
Omregningsformel for standardisering
Rumus penukaran pemiawaian
Rumus konversi standarisasi
m (2-VLE)
m20
2x + 3y = 4 2 ® 3 ® 4 ®
5x + 6y = 7 5 ® 6 ® 7
x = ? ® [x]
–1.
y = ? ® [y]
2.
det(D) = ? ® [det(D)]
–3.
m (3-VLE)
m21
x + y z = 9 1 ® 1 ® 1 ±® 9 ®
6x + 6y z = 17 6 ® 6 ® 1 ±® 17 ®
14x 7y + 2z = 42 14 ® 7 ±® 2 ® 42
x = ? ® [x]
3.238095238
y = ? ® [y]
–1.638095238
z = ? ® [z]
–7.4
det(D) = ? ® [det(D)]
105.
m (QUAD, CUBIC)
m22
3x
2
+ 4x 95 = 0 3 ® 4 ®± 95
x1 = ? ®
5.
x2 = ? ®
–6.333333333
5.
m23
5x
3
+4x
2
+3x +7=0 5 ® 4 ® 3 ® 7
x1 = ? ®
–1.233600307
i
x2 = ? ®
0.216800153
i
@≠
+
1.043018296
i
x3 = ? ®
0.216800153
i
@≠
1.043018296
i
m (CPLX)
m3
(126i) + (7+15i) 12 - 6 Ü+ 7 + 15 Ü-
(11+4i) = ( 11 + 4 Ü)= [x]
8.
i
@≠ [y]
+
5.
i
@≠ [x]
8.
i
6×(79i) × 6 *( 7 - 9 Ü)*
(5+8i) = ( 5 ±+ 8 Ü)= [x]
222.
i
@≠ [y]
+
606.
i
16×(sin30°+ 16 *(s 30 +
icos30°)÷(sin60°+ Üu 30 )/(s 60 +
icos60°)= Üu 60 )= [x]
13.85640646
i
@≠ [y]
+
8.
i
1
2
—— =
y
x
A
B
r
r2
θ1
θ2
r1
θ
••••
••••
••••
1
2
4
3
b
c
2
3
64
225
=
—– =
——– =
——– =
4
A
2
5
b
c
5
6
a
1
x + b
1
y = c
1
a
2
x + b
2
y = c
2
a
1
b
1
a
2
b
2
D =
a
1
x + b
1
y + c
1
z = d
1
a
2
x + b
2
y + c
2
z = d
2
a
3
x + b
3
y + c
3
z = d
3
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
D =
1
6
1
7
1
4
π
4
5
7
24
4+6
4
3
••••
••••
x =
Σx
n
y =
Σy
n
sy =
Σy
2
ny
2
n 1
sx =
Σx
2
nx
2
n 1
Σx = x
1
+ x
2
+ ··· + x
n
Σx
2
= x
1
2
+ x
2
2
+ ··· + x
n
2
Σxy = x
1
y
1
+ x
2
y
2
+ ··· + x
n
y
n
Σy = y
1
+ y
2
+ ··· + y
n
Σy
2
= y
1
2
+ y
2
2
+ ··· + y
n
2
σy =
Σy
2
ny
2
n
σx =
Σx
2
nx
2
n
••••
••••
This equipment complies with the requirements of Directive 89/336/
EEC as amended by 93/68/EEC.
Dieses Gerät entspricht den Anforderungen der EG-Richtlinie 89/336/
EWG mit Änderung 93/68/EWG.
Ce matériel répond aux exigences contenues dans la directive 89/336/
CEE modifiée par la directive 93/68/CEE.
Dit apparaat voldoet aan de eisen van de richtlijn 89/336/EEG,
gewijzigd door 93/68/EEG.
Dette udstyr overholder kravene i direktiv nr. 89/336/EEC med tillæg
nr. 93/68/EEC.
Quest’ apparecchio è conforme ai requisiti della direttiva 89/336/EEC
come emendata dalla direttiva 93/68/EEC.
      
    89/336/,  
      93/68/.
Este equipamento obedece às exigências da directiva 89/336/CEE na
sua versão corrigida pela directiva 93/68/CEE.
Este aparato satisface las exigencias de la Directiva 89/336/CEE
modificada por medio de la 93/68/CEE.
Denna utrustning uppfyller kraven enligt riktlinjen 89/336/EEC så som
kompletteras av 93/68/EEC.
Dette produktet oppfyller betingelsene i direktivet 89/336/EEC i
endringen 93/68/EEC.
Tämä laite täyttää direktiivin 89/336/EEC vaatimukset, jota on
muutettu direktiivillä 93/68/EEC.
чÌÌÓ ÛÒÚÓÈÒÚ‚Ó ÒÓÓÚ‚ÂÚÒÚ‚ÛÂÚ Ú·ӂ‡ÌËflÏ ‰ËÂÍÚË‚˚ 89/336/
EEC Ò Û˜ÂÚÓÏ ÔÓÔ‡‚ÓÍ 93/68/EEC.
Ez a készülék megfelel a 89/336/EGK sz. EK-irányelvben és annak 93/
68/EGK sz. módosításában foglalt követelményeknek.
Tento pfiístroj vyhovuje poÏadavkÛm smûrnice 89/336/EEC v platném
znûní 93/68/EEC.
In Europe:
Nur für Deutschland/For Germany only:
Umweltschutz
Das Gerät wird durch eine Batterie mit Strom versorgt.
Um die Batterie sicher und umweltschonend zu entsorgen,
beachten Sie bitte folgende Punkte:
Bringen Sie die leere Batterie zu Ihrer örtlichen Mülldeponie,
zum Händler oder zum Kundenservice-Zentrum zur
Wiederverwertung.
Werfen Sie die leere Batterie niemals ins Feuer, ins Wasser
oder in den Hausmüll.
Seulement pour la France/For France only:
Protection de l’environnement
Lappareil est alimenté par pile. Afin de protéger
lenvironnement, nous vous recommandons:
dapporter la pile usagée ou à votre revendeur ou au service
après-vente, pour recyclage.
de ne pas jeter la pile usagée dans une source de chaleur,
dans leau ou dans un vide-ordures.
AC + BD
< 10
100
C
2
+ D
2
(A+Bi)÷(C+Di)
BC AD
< 10
100
C
2
+ D
2
C
2
+ D
2
0
DEC DEC : | x | 9999999999
BIN BIN : 1000000000 x 1111111111
PEN 0 x 111111111
OCT PEN : 2222222223 x 4444444444
HEX 0 x 2222222222
AND OCT : 4000000000 x 7777777777
OR 0 x 3777777777
XOR HEX : FDABF41C01 x FFFFFFFFFF
XNOR 0 x 2540BE3FF
BIN : 1000000000 x 1111111111
0 x 111111111
PEN : 2222222223 x 4444444444
NOT
0 x 2222222221
OCT : 4000000000 x 7777777777
0 x 3777777777
HEX : FDABF41C01 x FFFFFFFFFF
0 x 2540BE3FE
BIN : 1000000001 x 1111111111
0 x 111111111
PEN : 2222222223 x 4444444444
NEG
0 x 2222222222
OCT : 4000000001 x 7777777777
0 x 3777777777
HEX : FDABF41C01 x FFFFFFFFFF
0 x 2540BE3FF
* n, r: integer / ganze Zahlen / entier / entero / inteiro / intero /
geheel getal / egész számok / celé číslo / heltal /
kokonaisluku / ˆÂÎ˚ / heltal /
/ /
/
integer / bilangan bulat
•••• ••••
••••
n!
(n-r)!
n!
(n-r)!
π
180
10
9
π
2
π
180
π
2
10
9
1
x
1
x
1
x
1
x
Endast svensk version/For Sweden only:
Miljöskydd
Denna produkt drivs av batteri.
Vid batteribyte skall följande iakttagas:
Det förbrukade batteriet skall inlämnas till er lokala handlare
eller till kommunal miljöstation för återinssamling.
Kasta ej batteriet i vattnet eller i hushållssoporna. Batteriet
får ej heller utsättas för öppen eld.
OPMERKING: ALLEEN VOOR NEDERLAND/
NOTE: FOR NETHERLANDS ONLY
Physical Constants and Metric Conversions are shown in the
tables.
Physikalischen Konstanten und metriche Umrechnungen sind
in der Tabelle aufgelistet.
Les constants physiques et les conversion des unités sont
indiquées sur les tableaux.
Las constants fisicas y conversiones métricas son mostradas
en las tables.
Constantes Fisicas e Conversões Métricas estão mostradas
nas tablelas.
La constanti fisiche e le conversioni delle unità di misura
vengono mostrate nella tabella.
De natuurconstanten en metrische omrekeningen staan in de
tabellen hiernaast.
A fizikai konstansok és a metrikus átváltások a táblázatokban
találhatók.
Fyzikální konstanty a převody do metrické soustavy jsou
uvedeny v tabulce.
Fysikaliska konstanter och metriska omvandlingar visas i
tabellerna.
Fysikaaliset vakiot ja metrimuunnokset näkyvät taulukoista.
Ç Ú‡·Îˈ‡ı ÔÓ͇Á‡Ì˚ ÙËÁ˘ÂÒÍË ÍÓÌÒÚ‡ÌÚ˚ Ë
ÏÂÚ˘ÂÒÍË ÔÂÓ·‡ÁÓ‚‡ÌËfl.
Fysiske konstanter og metriske omskrivninger vises i tabellen.
Pemalar Fizik dan Pertukaran Metrik ditunjukkan di dalam
jadual.
Konstanta Fisika dan Konversi Metrik diperlihatkan di dalam
tabel.
METRIC CONVERSIONS
x 1 44
No. UNIT No. UNIT No. UNIT
1incm 16 kglb 31 JcalIT
2cmin 17 °F°C32calITJ
3ftm18°C°F33hpW
4mft 19 gal (US)l 34 Whp
5ydm20lgal (US) 35 psW
6myd 21 gal (UK)l 36 Wps
7 milekm 22 lgal (UK) 37 kgf/cm
2
Pa
8kmmile 23 fl oz (US)ml 38 Pakgf/cm
2
9 n milem24mlfl oz (US) 39 atmPa
10 mn mile 25 fl oz (UK)ml 40 Paatm
11 acrem
2
26 mlfl oz (UK) 41 mmHgPa
12 m
2
acre 27 Jcal 42 PammHg
13 ozg 28 calJ 43 kgf·mJ
14 goz 29 Jcal15 44 Jkgf·m
15 lbkg 30 cal15J
7
5
1
8
1
3
PHYSICAL CONSTANTS ß 01 52
No. SYMBOL UNIT No. SYMBOL UNIT No. SYMBOL UNIT
01 - c, c
0
m s
1
19 -
µ
Β
J T
1
37 - eV J
02 - G m
3
kg
1
s
2
20 -
µ
e
J T
1
38 - t K
03 - g
n
m s
2
21 -
µ
Ν
J T
1
39 - AU m
04 - m
e
kg 22 -
µ
p
J T
1
40 - pc m
05 - m
p
kg 23 -
µ
n
J T
1
41 - M(
12
C) kg mol
1
06 - m
n
kg 24 -
µ
µ
J T
1
42 - h
-
J s
07 - m
µ
kg 25 -
λ
c
m43 - E
h
J
08 - lu kg 26 -
λ
c, p
m44 - G
0
s
09 - e C 27 -
σ
W m
2
K
4
45 -
α
1
10 - h J s 28 - N
Α
,
L mol
1
46 - m
p
/m
e
11 - k J K
1
29 - V
m
m
3
mol
1
47 - M
u
kg mol
1
12 -
µ
0
N A
2
30 - R J mol
1
K
1
48 -
λ
c, n
m
13 -
ε
0
F m
1
31 - F C mol
1
49 - c
1
W m
2
14 - r
e
m 32 - R
K
Ohm 50 - c
2
m K
15 -
α
33 -
-
e/m
e
C kg
1
51 - Z
0
16 - a
0
m 34 - h/2m
e
m
2
s
1
52 - Pa
17 - R
m
1
35 -
γ
p
s
1
T
1
18 - Φ
0
Wb 36 - K
J
Hz V
1
7


Need help? Post your question in this forum.

Forumrules


Report abuse

Libble takes abuse of its services very seriously. We're committed to dealing with such abuse according to the laws in your country of residence. When you submit a report, we'll investigate it and take the appropriate action. We'll get back to you only if we require additional details or have more information to share.

Product:

For example, Anti-Semitic content, racist content, or material that could result in a violent physical act.

For example, a credit card number, a personal identification number, or an unlisted home address. Note that email addresses and full names are not considered private information.

Forumrules

To achieve meaningful questions, we apply the following rules:

Register

Register getting emails for Sharp el 506w at:


You will receive an email to register for one or both of the options.


Get your user manual by e-mail

Enter your email address to receive the manual of Sharp el 506w in the language / languages: English as an attachment in your email.

The manual is 2,06 mb in size.

 

You will receive the manual in your email within minutes. If you have not received an email, then probably have entered the wrong email address or your mailbox is too full. In addition, it may be that your ISP may have a maximum size for emails to receive.

The manual is sent by email. Check your email

If you have not received an email with the manual within fifteen minutes, it may be that you have a entered a wrong email address or that your ISP has set a maximum size to receive email that is smaller than the size of the manual.

The email address you have provided is not correct.

Please check the email address and correct it.

Your question is posted on this page

Would you like to receive an email when new answers and questions are posted? Please enter your email address.



Info