Manual Stihl SR320 (page 31 of 44) (English)

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In this case 0.6 litres pesticide would have to be mixed

with 600 litres water to make up the spray solution.

However, in low-volume mistblowing only one quarter of

the water quantity is required for the same amount of

pesticide. This means that the concentration used is four

times higher than for high-pressure spraying. The 0.6

litres pesticide therefore have to be mixed with only 150

litres water. That is the quantity of solution required for

mistblowing 1 hectare. Finally, this quantity has to be

multiplied by the area to be treated in our example, i.e.

0.36 ha. The total quantity of solution to be applied to the

field is 54 litres.

Calculation

Area: 120 m • 30 m = 3,600 m

3,600 m

: 10,000 m

/ha = 0.36 ha

Solution/ha:

(acre): 0.6 l: 0.001 : 4 = 150 l

Required quan

tity of solution: 150 l/ha • 0.36 ha = 54 l

Note: If the area to be treated is smaller than 1 hectare,

the quantity of solution required is less than the quantity

of solution per hectare (acre).

Note: The increase in the strength of the mixture by a

factor of 4 was assumed for the purposes of this example.

Other mix ratios are possible in practical applications on

the basis of empirical values, special requirements or

explicit instructions.

The graph makes it easier to determine the quantity of

solution required. You can use a ruler and pencil to mark

in your own applications.

See enclosed graph 0457 352 0100

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Stihl SR320 Manual

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