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99
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93
melborP esuaCelbaborP noitcAevitcerroC egaP.feR
ehtgnitarepO
ylpmisrednammoC
natuptuoottisesuac
tonseoddnapeebrorre
ehtlortnocotuoywolla
.reviecsnartFH
1 ehtneewtebecnatsidegralooT
retropsnarTdnarednammoC
atadtcerrocstneverp
.snoitacinummoc
1 anihtiwrednammoCehtetarepO
owtehtswollatahtecnatsid
elacs-llufawohsotsreviecsnart
.gnidaerretem-S
2 tneverpsnoitidnocevawoidardaB
gniebmorfsdnammoclortnoc
.dettimsnartyltcerroc
2 sserP ]CNYS[ ehtdaerotyllanoisacco
.reviecsnartFHehtfosutats
78
oiduaraehtonnacuoY
FHehtybdeviecer
.reviecsnart
ehtnoSSCTCehtNOdehctiwsuoY
.rednammoCehtfodnabzHM441
sserP ]F[ , ]3[ .SSCTCehtFFOhctiwsot04
tonnacuoY
esopmirepus
ehtotnonoitamrofni
.rotinom1H-CV
retneyltcerrocotdeliafuoY
.desopmirepusebotnoitamrofni
retneyltcerrocot63ot13uneMesU
.noitamrofniderisedeht
95,85
margorptonnacuoY
VTSSahtiw1H-CVeht
.edom
.snoitcennocelbacdaB ehtroflaunamnoitcurtsniehtotrefeR
1H-CVehttcennocyltcerrocdna1H-CV
.reviecsnartehtot
75
Note: When two received frequencies have relationships per the equation below or other similar relationships, an internal heterodyne may be heard.
This is not a defect.
2 (f
U
– 45.05) – 4 (f
V
+ 38.85) = 38.85 or 45.05
(f
U
– 45.05) – 2 (f
V
+ 38.85) = 38.85
n (f
SV
– 45.05) – n (f
V
+ 38.85) = 38.85 or 45.05 where n = 3, 4, or 5.
f
V
= VHF frequency (band A)
f
U
= UHF frequency (band B)
f
SV
= VHF frequency (band B)
99


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